2 lines
85 B
TeX
2 lines
85 B
TeX
E\equiv\sum_i\dot{q_i}\frac{\partial L}{\partial \dot{q_i}}-L
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=\sum_i\dot{q}_i p_i-L
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E\equiv\sum_i\dot{q_i}\frac{\partial L}{\partial \dot{q_i}}-L
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=\sum_i\dot{q}_i p_i-L
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