149 lines
7.7 KiB
Markdown
149 lines
7.7 KiB
Markdown
---
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title: 30-motion-in-a-rapidly-oscillating-field
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---
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Motion in a rapidly oscillating field
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93
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bk2 = Oscillations exist only for € > Ek, and then b > bk. Since the state
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b = 0 is always stable, an initial "push" is necessary in order to excite oscillations.
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The formulae given above are valid only for small E. This condition is satisfied if 1 is small
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and also the amplitude of the force is such that 2/wo < A KWO.
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b
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B
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A
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€
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FIG. 34
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§30. Motion in a rapidly oscillating field
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Let us consider the motion of a particle subject both to a time-independent
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field of potential U and to a force
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f=f1coswt+fasin.ou
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(30.1)
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which varies in time with a high frequency w (f1, f2 being functions of the
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co-ordinates only). By a "high" frequency we mean one such that w > 1/T,
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where T is the order of magnitude of the period of the motion which the
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particle would execute in the field U alone. The magnitude of f is not assumed
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small in comparison with the forces due to the field U, but we shall assume
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that the oscillation (denoted below by $) of the particle as a result of this
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force is small.
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To simplify the calculations, let us first consider motion in one dimension
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in a field depending only on the space co-ordinate X. Then the equation of
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motion of the particle ist
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mx = -dU/dx+f.
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(30.2)
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It is evident, from the nature of the field in which the particle moves, that
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it will traverse a smooth path and at the same time execute small oscillations
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of frequency w about that path. Accordingly, we represent the function x(t)
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as a sum:
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(30.3)
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where (t) corresponds to these small oscillations.
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The mean value of the function (t) over its period 2n/w is zero, and the
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function X(t) changes only slightly in that time. Denoting this average by a
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bar, we therefore have x = X(t), i.e. X(t) describes the "smooth" motion of
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t The co-ordinate x need not be Cartesian, and the coefficient m is therefore not neces-
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sarily the mass of the particle, nor need it be constant as has been assumed in (30.2). This
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assumption, however, does not affect the final result (see the last footnote to this section).
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94
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Small Oscillations
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§30
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the particle averaged over the rapid oscillations. We shall derive an equation
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which determines the function X(t).t
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Substituting (30.3) in (30.2) and expanding in powers of & as far as the
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first-order terms, we obtain
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(30.4)
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This equation involves both oscillatory and "smooth" terms, which must
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evidently be separately equal. For the oscillating terms we can put simply
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mg = f(X, t);
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(30.5)
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the other terms contain the small factor & and are therefore of a higher order
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of smallness (but the derivative sur is proportional to the large quantity w2
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and so is not small). Integrating equation (30.5) with the function f given by
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(30.1) (regarding X as a constant), we have
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& = -f/mw2.
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(30.6)
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Next, we average equation (30.4) with respect to time (in the sense discussed
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above). Since the mean values of the first powers of f and $ are zero, the result
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is
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dX
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which involves only the function X(t). This equation can be written
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mX = dUeff/dX,
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(30.7)
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where the "effective potential energy" is defined ast
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Ueff = U+f2/2mw2
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=
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(30.8)
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Comparing this expression with (30.6), we easily see that the term added to
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U is just the mean kinetic energy of the oscillatory motion:
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Ueff= U+1mg2
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(30.9)
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Thus the motion of the particle averaged over the oscillations is the same
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as if the constant potential U were augmented by a constant quantity pro-
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portional to the squared amplitude of the variable field.
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t The principle of this derivation is due to P. L. KAPITZA (1951).
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++ By means of somewhat more lengthy calculations it is easy to show that formulae (30.7)
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and (30.8) remain valid even if m is a function of X.
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§30
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Motion in a rapidly oscillating field
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95
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The result can easily be generalised to the case of a system with any number
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of degrees of freedom, described by generalised co-ordinates qi. The effective
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potential energy is then given not by (30.8), but by
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Unt = Ut
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= U+ ,
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(30.10)
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where the quantities a-1ik, which are in general functions of the co-ordinates,
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are the elements of the matrix inverse to the matrix of the coefficients aik in
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the kinetic energy (5.5) of the system.
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PROBLEMS
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PROBLEM 1. Determine the positions of stable equilibrium of a pendulum whose point of
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support oscillates vertically with a high frequency y
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(g/l)).
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SOLUTION. From the Lagrangian derived in §5, Problem 3(c), we see that in this case the
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variable force is f = -mlay2 cos yt sin (the quantity x being here represented by the angle
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b). The "effective potential energy" is therefore Ueff = mgl[-cos - & st(a2y2/4gl) sin2]. The
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positions of stable equilibrium correspond to the minima of this function. The vertically
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downward position ( = 0) is always stable. If the condition a2y2 > 2gl holds, the vertically
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upward position ( = ) is also stable.
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PROBLEM 2. The same as Problem 1, but for a pendulum whose point of support oscillates
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horizontally.
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SOLUTION. From the Lagrangian derived in §5, Problem 3(b), we find f = mlay2 cos yt
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cos and Uell = mgl[-cos 3+(a2y2/4gl) cos2]. If a2y2 < 2gl, the position = 0 is stable.
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If a2y2 > 2gl, on the other hand, the stable equilibrium position is given by cos = 2gl/a22.
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CHAPTER VI
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MOTION OF A RIGID BODY
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$31. Angular velocity
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A rigid body may be defined in mechanics as a system of particles such that
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the distances between the particles do not vary. This condition can, of course,
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be satisfied only approximately by systems which actually exist in nature.
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The majority of solid bodies, however, change so little in shape and size
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under ordinary conditions that these changes may be entirely neglected in
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considering the laws of motion of the body as a whole.
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In what follows, we shall often simplify the derivations by regarding a
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rigid body as a discrete set of particles, but this in no way invalidates the
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assertion that solid bodies may usually be regarded in mechanics as continu-
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ous, and their internal structure disregarded. The passage from the formulae
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which involve a summation over discrete particles to those for a continuous
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body is effected by simply replacing the mass of each particle by the mass
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P dV contained in a volume element dV (p being the density) and the sum-
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mation by an integration over the volume of the body.
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To describe the motion of a rigid body, we use two systems of co-ordinates:
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a "fixed" (i.e. inertial) system XYZ, and a moving system X1 = x, X2 = y,
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X3 = 2 which is supposed to be rigidly fixed in the body and to participate
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in its motion. The origin of the moving system may conveniently be taken
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to coincide with the centre of mass of the body.
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The position of the body with respect to the fixed system of co-ordinates
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is completely determined if the position of the moving system is specified.
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Let the origin O of the moving system have the radius vector R (Fig. 35).
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The orientation of the axes of that system relative to the fixed system is given
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by three independent angles, which together with the three components of
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the vector R make six co-ordinates. Thus a rigid body is a mechanical system
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with six degrees of freedom.
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Let us consider an arbitrary infinitesimal displacement of a rigid body.
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It can be represented as the sum of two parts. One of these is an infinitesimal
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translation of the body, whereby the centre of mass moves to its final position,
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but the orientation of the axes of the moving system of co-ordinates is un-
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changed. The other is an infinitesimal rotation about the centre of mass,
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whereby the remainder of the body moves to its final position.
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Let r be the radius vector of an arbitrary point P in a rigid body in the
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moving system, and r the radius vector of the same point in the fixed system
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(Fig. 35). Then the infinitesimal displacement dr of P consists of a displace-
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ment dR, equal to that of the centre of mass, and a displacement doxr
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96
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